Explain the radius of gyration.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The radius of gyration is a parameter that describes how the mass of a rotating rigid body is distributed with respect to the axis of rotation.
It is related to the moment of inertia $(I)$ and the total mass $(M)$ of the body.
Consider a rigid body rotating about a given axis,consisting of $n$ particles,each of mass $m$. The total mass of the rigid body is $M = n m$.
The moment of inertia about the given axis is:
$I = m_{1} r_{1}^{2} + m_{2} r_{2}^{2} + \ldots + m_{n} r_{n}^{2}$
Since $m_{i} = m$ for all particles:
$I = m r_{1}^{2} + m r_{2}^{2} + \ldots + m r_{n}^{2} = m (r_{1}^{2} + r_{2}^{2} + \ldots + r_{n}^{2})$
By multiplying and dividing by $n$:
$I = (m n) \left[ \frac{r_{1}^{2} + r_{2}^{2} + \ldots + r_{n}^{2}}{n} \right]$
We define the radius of gyration $k$ such that $k^2 = \frac{r_{1}^{2} + r_{2}^{2} + \ldots + r_{n}^{2}}{n}$.
Thus,the moment of inertia is given by:
$I = M k^{2}$
Here,$k$ represents the root mean square distance of the particles from the axis of rotation.

Explore More

Similar Questions

Four hollow spheres,each with a mass of $1\, kg$ and a radius $R = 10\, cm$,are connected with massless rods to form a square with a side of length $L = 50\, cm$. In case-$1$,the masses rotate about an axis that bisects two sides of the square. In case-$2$,the masses rotate about an axis that passes through the diagonal of the square,as shown in the figure. Compute the ratio of the moments of inertia $I_1/I_2$ for the two cases.

If a person sitting on a rotating stool with his hands outstretched, suddenly lowers his hands, then his

What is the radius of gyration of a circular disc of radius $R$ about an axis passing through its center and perpendicular to its plane?

The moment of inertia of a solid sphere about its diameter is $I$. It is then recast into $27$ small spheres of the same diameter. The moment of inertia of each small sphere about its diameter is:

The figure shows an isosceles triangular plate of mass $M$ and base $L$. The angle at the apex is $90^o$. The apex lies at the origin and the base is parallel to the $X$-axis. The moment of inertia of the plate about the $z$-axis is

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo